The daily heat required is:
1) for a very lazy person:
female = weight (KG)*29; male = weight(KG)*32
2) for a lazy person:
female = weight(KG)*31; male = weight(KG)*34
3) for moderate sport person:
female = weight(KG)*24; male = weight(KG)*37
4) for active sport person:
female = weight(KG)*36; male = weight(KG)*40
example:a very lazy female,her weight is 55kg,
then the heat that she required is:
55kg * 31 = 1705 Kcal,means that 1705kcal is daily calories usage
if she intake calories same with 1705kcal,
weight will maintain ;
more than 1705kcal, weight will increase;l
ess than 1705kcal , her weight will decrease.
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